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Efectuati
X+1 3-2x
__ + ___ =
X-2. 5x-10


Răspuns :

[tex] \frac{x + 1}{x - 2} + \frac{3 - 2x}{5x - 10} [/tex]

[tex] = \frac{5(x + 1)}{5(x - 2)} + \frac{3 - 2x}{5x - 10} [/tex]

[tex] = \frac{5x + 5}{5x - 10} + \frac{3 - 2x}{5x - 10} [/tex]

[tex] = \frac{5x + 5 + 3 - 2x}{5x - 10} [/tex]

[tex] = \frac{3x + 8}{5x - 10} [/tex]
[tex]\frac{x+1}{x-2}+ \frac{3-2x}{5x-10}= \frac{x+1}{x-2}+ \frac{3-2x}{5(x-2)}= \\ \\ \frac{ ^{5)} x+1}{x-2}+ \frac{3-2x}{5(x-2)}=\frac{ 5x+5}{5(x-2)}+ \frac{3-2x}{5(x-2)}= \\ \\ \frac{ 5x+5+3-2x}{5(x-2)}= \frac{3x+8}{5(x-2)} = \\ \\ \frac{x+1}{x-2}+ \frac{3-2x}{5x-10}= \frac{3x+8}{5(x-2)}[/tex]

[tex]\frac{x+1}{x-2}+ \frac{3-2x}{5x-10}= \frac{3x+8}{5x-10}[/tex]