Se da............
Vs = 200mL
C = 28%
ρ = 1,31g/cm³
Cf = 50%
ρf = 1,54/cm³
ρ = ms/Vs ⇒ ms = ρ×Vs = 1,31×200 = 262g sol. NaOH
C = md/ms×100 ⇒ md = C×ms/100 = 28×262/100 = 73,36g
Cf = mdi+md ad/msi+ md ad ×100
50 = (73,36+md ad)/(262+md ad) ×100
50(262+md ad) = 100(73,36+md ad)
13100+50md ad = 7336+100md ad
50 md ad = 5764 ⇒ md ad = 5764/50 = 115,28g NaOH
msf = msi+md ad = 262+115,28 = 377,28g
ρf = msf/Vs ⇒ Vs = msf/ρf = 377,28/1,54 = 244,987 ≈ 245 mL
