a = 5√3; b = 7/3; c = √75 = 5√3; d = 2,(3) = ( 23-2)/9=21/9 = 7/3
a) a + b = c + d ( Adevarat)
b) a - b = c - d (Adevarat) ⇔ 5√3 - 7/3 = √75 - 2,(3)
c) a - c = d ( Fals)
e) ab = cd (A)
f) a : b = d : c ( Fals) ⇔ 5√3 : 7/3 ≠ 2,(3) : √75
g) 3 a = 3 c ( Adevarat) ⇔ 3 × 5√3 = 3 × √75
h) - ( 1/2) b = - ( 1/2) d ( Adevarat)
i) a/7 = c/7 ( Adevarat) ⇔ 5√3/7 = √75/7