Sper ca am inteles problema... nu am putut sa vad tot continutul...
Notam cu D DRUMUL
In ziua 1 a parcurs (3/7)D
In ziua 2 a parcurs (4/7)[D - (3/7)D]
In ziua a 3 a a parcurs 457 km
D = (3/7)D + (4/7)[D - (3/7)D] + 457 à
D = (3/7)D + (4/7) [ (7D-3D)/7] +457 à
D = (3/7)D + (4/7)(4D/7)+457à
D = (3/7)D + (16D/49) +457àD= (21D+16D)/49 + 457à
D = (37D)/49 + 457 à D-(37D)/49 =
457 à
(49D-37D)/49 = 457 à 12D/49 = 457 à
D= (49*457)/12 à D = 1866,08 km
