g)
(2+3/8:1/2)×20=
=(2/1+3/8×2/1)×20/1=
=(2/1+ 3×1 totul supra/4×1)×20/1=
=(2/1+3/4)×20/1=
=4×2+3 tot asta supra/4 × 20/1=
=8+3 totul supra/4 × 20/1=
=11/4×20/1=
=11×5 totul supra/1×1=
=55/1=
=55
i)
(2+2/5)×(1/2+1/3):4=
=(2/1+2/5)× 3×1+2×1 tot asta supra/6 : 4/1=
=5×2+2 tot asta supra/5 × 5/6 ×1/4=
=12/5×5/6×1/4=
=2×1 totul supra/1×1 × 1/4=
=2/1 ×1/4=
=1×1 totul supra/1×2=
=1/2
l) scuze am crezut ca e i
(1/2+3/5)×30/22+1/2:(2/5-1/10)=
=5×1+2×3 tot asta supra/10 ×30/22 +1/2: 2×2-1 tot asta supra/10=
=5+6 totul supra/10×30/22 +1/2:3/10=
=11/10×30/22 + 1/2×10/3=
=1×3 totul supra/1×2 + 1×5 totul supra/1×3=
=3/2 + 5/3 =
=3×3+2×5 tot asta supra/6=
=9+10 totul supra/6=
=19/6
n)
[1/10+2/5 ×(2/3-1/4)]:2 întregi 1/2=
=(1/10+2/5× 4×2-3×1 tot ăsta supra/12): 2×2+1 tot asta supra/2=
=(1/10+2/5× 8-3 totul supra/12): 5/2=
=(1/10 + 2/5× 5/12)×2/5=
=(1/10 + 1×1 totul supra/1×6)×2/5=
=(1/10+ 1/6)×2/5=
=3×1+5×1 tot asta supra/30 × 2/5=
=3+5 totul supra/30 × 2/5=
=8/30 × 2/5=
=8×1 totul supra/15×5=
=8/75
