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Maria si Dan au impreuna 35 nuci.Cite nuci au fiecare daca Dan are de 4ori mai multe?

Răspuns :

M |-----|
D |-----|-----|-----|-----|         } 35.

35 : 5 = 7 nuci ( are Maria)
7 x 4 = 28 nuci ( are Dan )
Verificare : 7 + 28 = 35 nuci .
Metoda algebrică:

M+D=35 nuci
D=4M
___________
M+4M=35 nuci
5M=35 nuci
M=35:5
M=7 nuci
D=7×4
D=28 nuci

Metoda grafică:

M |-------| } 35 nuci
D |-------|-------|-------|-------|

35:5=7 nuci (un segment)

M=7 nuci
D=7×4
D=28 nuci