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cati moli de apa se gasesc in 90 g apa

Răspuns :

m=90 g [tex]H_{2}O[/tex]

[tex]M_{H_{2}O}=2\cdot 1+16=2+16=18[/tex]

n=[tex]\dfrac{m}{M}[/tex]

n= [tex]\dfrac{90}{18}[/tex]=5 moli
v(cantitatea de substanta) =m ÷M(masa molară)
M(apei) =18g/mol
v=90g÷18g/mol=5mol
v(apa)=5mol
Succes!!!