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Daca x+y = 1 ,calculati valoarea numarului:
a=(2x+2y)+(3x+3y)la purerea 2 + (4x+4y) la puterea 3..
Help pls.. nu inteleg cum as putea face..


Răspuns :

a=(2x+2y)+(3x+3y)^2+(4x+4y)^3
a=[2×(x+y)]+[3×(x+y)]^2+[4(x+y)]^3
a=2×1+(3×1)^2+(4×1)^3
a=2+3^2+5^3
a=2+9+125
a=136