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Calculați Compozitia procentuala alcool metilic

Răspuns :

CH3OH   sau   CH4O
M=12gC+4gH+ 16gO---> 32g/mol
in 32g alcool.........12gC.....4gH......16gO
  100G...................x...........Y............z
x= 12x100/32=
y= 4x100/32=
z=16x100/32=
CALCULEAZA !!!!!!