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Combinari de n+1 luate câte n + Combinari de n+1 luate câte 1

Răspuns :

C de n+1 luate cate n=(n+1)!/n!*(n+1-n)!=n!(n+1)/n!*1!=n+1
C de n+1 luate cate 1=(n+1)!/1!*(n+1-1)!=n!(n+1)/n!=n+1
Rezultatul este: n+1+n+1=2n+2