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va rog cu segmente,corect!!!!

Va Rog Cu Segmentecorect class=

Răspuns :

I+II+III=920
I=1 parte+1parte+1parte
II=1parte
III=1parte+1parte+1parte+1parte+1parte+1parte
10parti=920
1parte=920:10
1parte=92
I=92•3
I=276
II=92
III=92•6
III=552
/__/__/__/ prima
/__/ a doua
/__/__/__/__/__/__/ a treia
Total 920 muncitori
3+1+6=10 segmente egale
920:10=92 in segment ( a doua fabrica)
92×3=276 prima fabrica
92×6=552 a treia fabrica
V 276+92+552=920 muncitori