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daca a+3b=19 si b+2c=17,calculati 2a+9b+6c

Răspuns :

a+3b+a+3b+b+2c+b+2c+b+2c= 89 la acest calcul
a+3b=19
b+2c=17

2a+9b+6c = ?

a+a+3b+3b+b+b+b+2c+2c+2c=

(a+3b) + (a+3b) + (b+2c) + (b+2c) + (b+2c) =

19+19+17+17+17 = 89

2a+9b+6c = 89