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Se nitreaza 3 moli de toluent cu un randament de 80%. Ce cantitate de TNT se obtine in urma reactiei?

Răspuns :

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Vezi imaginea ADRIA26
C₆H₅-CH₃ + 3HO-NO₂ ⇒ TNT + 3H₂O

teoretic : n toluen = n TNT = 3 moli

practic: η = np/nt×100 ⇒ np = η×nt/100 = 80×3/100 = 2,4 moli TNT

m TNT = 2,4×227 = 544,8g

MC₆H₅(NO₂)₃  = 227g/mol