3.
a) BD=3/5 cm, DC=4/15 cm
BC=BD+DC=3/5 + 4/15=13/15 cm
teorema inaltimii AD
AD^2=BD x DC=12/75
AD=2/5 cm
b) BD=8/3 cm, BC=25/6 cm
DC=BC-BD=25/6 - 8/3
DC=3/2 cm
AD=√(BD x DC)=√(8/3 x 3/2)=2 cm
c) BD=4/5 cm, AD=12/5 cm
AD^2=BD x DC
DC=(144/25)/(4/5)=36/5 cm
BC=BD+DC=4/5+36/5=8 cm
4.
a) BD=2√3 cm, BC=8√3 cm
DC=BC-BD=6√3 cm
AD=√(BD x DC)=√(2√3 x 6√3)=6 cm
b) AD=6 cm, BD=4 cm
AD^2=BD x DC
DC=AD^2/BD=36/4=9 cm
c) AD=3√3 cm, DC=3 cm
AD^2=BD x DC
BD=AD^2/DC=27/3=9 cm