a)
[tex] \frac{2}{7} + \frac{1}{7} + \frac{3}{7} + \frac{4}{7} = \frac{2 + 1 + 3 + 4}{7} = \frac{9}{7} [/tex]
b)
[tex] \frac{1}{8} + 1 + \frac{3}{8} + \frac{4}{8} = \frac{1 + 8 + 3 + 4}{8} = \frac{16}{8} = 2[/tex]
Amplificam 1 cu 8
c)
[tex]1 - ( \frac{7}{6} + \frac{4}{6} - \frac{3}{6} ) = \frac{1}{1} - \frac{7 + 4 - 3}{6} = \frac{1}{1} - \frac{8}{6} = \frac{6 - 8}{6} = - \frac{2}{6} [/tex]
d)
[tex]x + \frac{3}{9} = \frac{6}{9} - \frac{1}{9} \\ x = \frac{5}{9} - \frac{3}{9} = \frac{2}{9} [/tex]
e)
[tex]x - \frac{8}{12} = \frac{5}{12} + 1 \\ x = \frac{17}{12} + \frac{8}{12} = \frac{25}{12} [/tex]
