[tex]\it \dfrac{423}{25} = 16\dfrac{23}{25} \Rightarrow inegalitatea\ devine:
\\ \\ \\
16\dfrac{\overline{8a}}{90} \ \textless \ 16\dfrac{23}{25} \Rightarrow \dfrac{\overline{8a}}{90} \ \textless \ \dfrac{23}{25} \Rightarrow \dfrac{\overline{8a}}{90} \ \textless \ 0,92 \Rightarrow \overline{8a} \ \textless \ 0, 92\cdot 90 \Rightarrow
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\overline{8a} \ \textless \ 82,8 \Rightarrow a\in\{0,\ 1,\ 2\}[/tex]
