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afla suma a patru numere pare consecutive stiind ca suma dintre primul si ultimul numar este 558.rezolvare cu segmente

Răspuns :

a/...../
a/..../+2
a/.../+2+2
a/.../+2+2+2
a+a+6=558
2a=558-6=552
a=552:2
a=276
b=278
c=280
d=282
a+b+c+d=?
a+d=558
________________________
a=?
b=?
c=?
d=?
___________________________

a/...../
a/..../+2
a/.../+2+2
a/.../+2+2+2
a+a+6=558
2a=558-6=552
a=552:2
a=276
b=278
c=280
d=282
V:276+278+280+282=1116
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