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Efectuati


a) 22 supra 36 X 1 supra 3 X 81 supra 11 =


b) 50 supra 26 X 1 supra 10 X 2 supra 15 =





dau coroana


Răspuns :

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Vezi imaginea EAGLEEYES
a(
[tex]a) \: \: \frac{22}{36} \times \frac{1}{3} \times \frac{81}{11} = \frac{22}{108} \times \frac{81}{11} = \frac{1782}{1188} simplificat \: prin6 = \frac{297}{298} [/tex]
b)
[tex] \frac{50}{26} \times \frac{1}{10} \times \frac{2}{15} = \frac{50}{260} \times \frac{2}{15} = \frac{10}{390} = \frac{1}{39} [/tex]