👤

Verifica egalitatile
12·3·10-(100+35:5)=50·2+25·4+(309-200-8·7)


Răspuns :

12x3x10-(100+35:5)=50x2+25x4+(309-200-8x7)
36x10-(100+7)=100+100+(109-56)
360-107=200+53
253=253
Este corect.
35:5=7
100+7=107
12×3=36
36×10=360 (deci t1 e 360)
8×7=56
309-200=109
109-56=53
50×2=100
25×4=100
100+100=200
200+53=253
=>F