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dau coronita aflati n 2*5 1 supra 6 =10nsupra 6

Răspuns :


2·5[tex]\dfrac{1}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]

10[tex]\dfrac{1}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]

[tex]\dfrac{61}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]

10n=[tex]\dfrac{61\cdot 6}{6}[/tex]

10n=61

n=[tex]\dfrac{61}{10}[/tex]=6,1
2 * 5intreg 1/6 = 10n/6
5intreg 1/6= (5x6+1)/6= 31/6
2* 31/6 = 10n /6
62/6  = 10n/6
10n = ( 62 x6)/6
10n = 62
n=62/10