Efectuăm operațiile din membrul stâng:
[tex]\it \left(\dfrac{1}{5}\right)^0 +\dfrac{1}{2}:2=1+\dfrac{1}{2}:\dfrac{2}{1} =1+\dfrac{1}{2}\cdot\dfrac{1}{2}= 1+\dfrac{1}{4} =\dfrac{5}{4} [/tex]
Efectuăm operațiile din membrul drept:
[tex]\it \left(1\dfrac{1}{3}x+\dfrac{1}{4}x\right)\cdot\dfrac{8}{19}+\dfrac{1}{3}x = \left(\dfrac{^{4)}4x}{\ 3}+\dfrac{^{3)}x}{\ 4}\right)\cdot\dfrac{8}{19}+\dfrac{x}{3} = \\\;\\ \\\;\\ =\dfrac{19x}{12}\cdot\dfrac{8}{19}+\dfrac{x}{3} =\dfrac{2x}{3}+\dfrac{x}{3}=\dfrac{3x}{3} =x[/tex]
Acum, vom avea :
[tex]\it \dfrac{5}{4}=x \Longleftrightarrow x=\dfrac{5}{4} \Longleftrightarrow x= 1,25[/tex]
