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[tex]8 {}^{x} = 4 {}^{2x \ + 1} [/tex]


Răspuns :

[tex]8^{x}=4^{2x+1}\\
\\ (2^{3})^{x}=(2^{2})^{2x+1}\\
\\ 2^{3x}=2^{2(2x+1)}\\
\\ 2^{3x}=2^{4x+2}\\
\\ \Rightarrow 3x=4x+2\\
\\ -2=4x-3x\\
\\ \boxed{x=-2},~S=\{-2\}[/tex]