5 intregi si 2/3 = ( 5 x 3 + 2)/3 = 17/3
1,(5)= (15-1)/9 = 14/9
15 intregi si 2/3 = ( 15 x 3 + 2 ) /3 = 47/3
( 17/3 - 14/9 - 2 ) × 47/3= → cmmmc (3, 9) = 27, aduc fractiile la acest numitor comun
= [ ( 17 x 9) /( 3 x 9) - ( 14 x 3)/( 9 x 3) - ( 2 x 27) / 27) × 47/3=
= ( 153/27 - 42/27 - 54/27 ) × 47/3 =
= 57/27 ×47/3 = → simplific pe 57 cu 3 = 19
= 19/27 × 47 = 893/27 = 33 intregi si 2/27 = 33, (074)
