Metoda algebrica:
a + b = 192
a : b = 2 rest 12
a = 2×b+12 (conform T.I.R)
2×b+12 + b = 192
3×b = 192-12
3×b = 180
b = 180 : 3
b = 60
a = 192 - 60
a = 132
Metoda grafica:
a /------/------/+12
b /------/
avem 3 segmente egale + 12 = 192
192 - 12 = 180
180 : 3 = 60 (valoarea unui segment egal)
a = 2×60+12 = 120+12 = 132
b = 60
Verificam:
132 + 60 = 192
132 : 60 = 2 rest 12
