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Aflati ,,a" din urmatoarele egalitatii:(5×a)+816+(86405-85798)×101=63468,21-a:[9371-10×(28×46-13×27)]=20.

Răspuns :

(5×a)+816+(86405-85798)×101=63468

(5×a)+816+607×101= 63468

(5×a)+816+61307= 63468

(5×a)+62123= 63468

5×a=63468- 62123

5×a=1345

a=1345:5

a=269


PROBĂ :


(5×269)+816+(86405-85798)×101=

=1345 +816+607×101

=2161+61307

=634068 (adevărat )








21-a:[9371-10×(28×46-13×27)]=20

a: [9371-10×(1288-351)]=21-20

a: [9371-10×(1288-351)]=1

a:(9371-10×937)=1

a:(9371-9370)=1

a:1=1

a=1×1

a=1


(5 × a) + 816 +(86 405 - 85 798) × 101= 63 468
(5 × a) + 816 + 607×101= 63 468
(5 × a) + 816 + 61 307= 63 468
5 × a = 63 468 - 61 307 - 816
5 × a = 2 161 - 816
5 × a =1 345
a =1 345 : 5
a = 269


21 - a : [9 371 - 10 × ( 28 × 46 - 13 × 27)]=20
a : [ 9 371 - 10 
× ( 1 288 - 351)] = 21 - 20 
a : ( 9 371 - 10 × 937) = 1 
a : ( 9 371 - 9 370) = 1
a : 1 = 1
a = 1 x 1
a = 1