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x + 1/x =2 => x^8+1/x^8=?

Răspuns :

[tex]x+\frac{1}{x}=2 \Leftrightarrow x^2+1=2*x \Leftrightarrow x^2-2*x+1=0\\ \Leftrightarrow (x-1)^2=0 \Rightarrow x=1[/tex]
Prin urmare:
[tex]x^8+\frac{1}{x^8}=1^8+\frac{1}{1^8}=1+1=2[/tex]