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(x+2)×(x-3)×(x-3) Va rog ajutati-ma

Răspuns :

(x^2-3x+2x-6)*(-3)= (x^2-x+6)*(x-3)=X^3-3x^2-x^2+3x-6x-18=x^3-4x^2-3x-18
(x+2)(x-3)(x-3)
= (x+2)(x-3)^{2}
= (x+2)(x^{2}-2*3x+3^{2})
= (x+2)(x^{2}-6x+9)
= x^{3}-6x^{2}+9x+2x^{2}-12x+18
= x^{3}-4x^{2}-3x+18