1mol 2 mol 1 mol 1 mol
Zn + 2 HCl => ZnCl2 + H2
n= m/M
n=nr moli
m= masa in grame
M=masa molara a substantei/elementului
n HCl= 16.2/36.5 = 0.444 mol
1 mol Zn consuma 2 mol HCl
x mol Zn consuma 0.444 mol HCl
x= (1*0.444)/2
x= 0.222 mol Zn metalic (cantitatea de Zn consumata)
m= n*M
m Zn = 0.222 * 65.38 = 14.51 g Zn (masa de Zn consumata)