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Fie punctele A(2,3),B(-3,4).Calculati distanta de la A la B.

Răspuns :

AB=√[(xB-xA)²+(yB-yA)²]

AB=√[(-3-2)²+(4-3)²]
AB=√(5²+1²)
AB=√26
Folosim LaTeX.

[tex]\it AB^2 = (x_B-x_A)^2 +(y_B-y_A)^2 = (-3-2)^2 + (4-3)^2 = 25+1= \\\;\\ = 26 \Longrightarrow AB = \sqrt{26}[/tex]