15/8 = 1 intreg si 7/8, deoarece 15 /8 = 8/8 + 7/8 = 1 intreg + 7/8
21/11 = 1 intreg si 10/11, deoarece 21/11 = 11/11 + 10/11
49/6 = 8 intregi si 1/6 , ⇒ 48/6 + 1/6 = 8 intregi + 1/6
38/11 = 3 intregi si 5/11; ↔ 33/11 + 5/11 → de 3 ori 11/11=33/11
63/22 = 2 intregi si 19/22→ 2 ×22/22 + 19/22
135/21 = 6 intregi si 9/21→ 135/21 - 6 × 21/21 = 135 /21 - 126/21 = 9/21
235/4 = 58 intregi si 3/5
→ pentru a afla intregii impart numaratorul la numitor
235 : 4 = 58 rest 3
85/7= 12 intregi si 1/7
85 : 7 = 12 rest 1
493/2 = 246 intregi si 1/2
493: 2 =246 rest 1
5204/3 = 1 734 intregi si 2/3
5 204 : 3 = 1 734 rest 2
107/21= 5 intregi si 2/21
107 : 21 = 5 rest 2
