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In triunghiul ABC ,punctele m€ab si n€ac ,astfel incat mn ||bc.Daca AM/MB=2/3 si an =12cm ,calculati nc si ac

Răspuns :

[tex] mn ||bc ⇒\frac{AM}{MB} [/tex]=[tex] \frac{AN}{NC} [/tex]⇔[tex] \frac{2}{3}= \frac{12}{NC} [/tex]⇒NC= 18 Deci AC = NC+AN = 12+18=30