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fie a multimea solutiilor reale ale ecuatiei 4x^2+3x-10=0

Răspuns :

Buna!
e ecuatie de gradul 2 asadar calculam delta.
Δ = 9 + 4*10*4 = 169 =[tex] 13^{2} [/tex]
asadar, [tex] x_{1} [/tex] = [tex] \frac{-3 + \sqrt{169} }{8} [/tex] =[tex] \frac{10}{8} [/tex] = [tex] \frac{5}{4} [/tex]  
si [tex] x_{2} [/tex] = [tex] \frac{-3 - \sqrt{169} }{8} [/tex] =[tex] \frac{-16}{8} [/tex]= - 2
deci, A = { -2 , [tex] \frac{5}{4} [/tex] }
4x²+3x-10=0
∆=b²-4ac
∆=3²-4·4·(-10)
∆=9+160=169
x1=(-b-√∆)/2a=(-3-13)/8=-16/8=-2
x2=(-b+√∆)/2a=(-3+13)/8=10/8=5/4
a={-2; 5/4}