s.o = 4,84g
a = 14,08g CO₂
b = 3,96g H₂O
VN₂ = 448mL = 0,448L
n = m/M = V/Vm ⇒ m = M*V/Vm = 28*0,448/22,4 = 0,56g N₂ = x
14,08g CO₂....................xg C
44g CO₂.......................12g C
x= 3,84g C
18g H₂O......................2g H
3,96g H₂O....................yg H
y = 0,44g H
mO = 4,84-0,44-3,84-0,56 = 0 (nu contine oxigen)
C: 3,84/12 = 0,32 ||: 0,04 => 8 atomi C
H: 0,44/1 = 0,44 ||: 0,04 => 11 atomi H
N: 0,56/14 = 0,04 ||:0,04 => 1 atom N
F.B => (C8H11N)n
F.M pt n=1 => C8H11N