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simplificati fractiile: 3^n+3^n+2+3^n+3+3^n+4 supra 3×7^n+7^n+1+7^n+2

Răspuns :

(3^n+3^n+2+3^n+3+3^n+4) /( 3×7^n+7^n+1+7^n+2 )=
=3^n(1+3^2+3^3+3^4)/[7^n(3+7+7^2)]
=3^n(1+9+27+81)/[7^n(10+49)]
=3^n
·118/(7^n·59)    |:59
=2·3^n/7^n