[tex] \frac{x + 1}{3} + \frac{x}{2} = 1 \frac{1}{6} - x \\ \frac{2(x + 1)}{6} + \frac{3x}{6} = \frac{7}{6} - \frac{6x}{6} \\ 2x + 2 + 3x = 7 - 6x \\ 5x + 2 = 7 - 6x \\ 5x + 6x = 7 - 2 \\ 11x = 5 \\ = > x = \frac{5}{11} [/tex]
Din cerinta ta nu reiese daca x este in fractie sau nu. De aceea rezolv in ambele moduri si alegi tu varianta corecta.
[tex]x + \frac{1}{3} + \frac{x}{2} = \frac{7}{6} - x \\ 6x + 2 + 3x = 7 - 6x \\ 9x +2 = 7 - 6x \\ 15x = 5 \\ x = \frac{1}{3} [/tex]
