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1/2+1/2 la patrat+1/3 la cub+.........1/2 la puteria 2018=?

Va rog frumos!!!


Răspuns :

1/2( 1+(1/2)+(1/2)²+...+(1/2)^2017)= (1/2)* (1-(1/2)^2018)/(1-1/2)=
 
=1-(1/2)^2018= (2^2018-1)/(2^2018)