[tex]\displaystyle\\
\frac{1}{2} \cdot \left\{\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} \right\}+\frac{1}{2^{13}}=\frac{1}{2^{12}}\\\\\\
\frac{1}{2} \cdot \left\{\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} \right\}=\frac{1}{2^{12}}-\frac{1}{2^{13}}\\\\\\
[/tex]
[tex]\displaystyle\\
\frac{1}{2} \cdot \left\{\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} \right\}=\frac{2}{2^{13}}-\frac{1}{2^{13}}\\\\\\
\frac{1}{2} \cdot \left\{\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} \right\}=\frac{1}{2^{13}}
[/tex]
[tex]\displaystyle\\
\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} =\frac{1}{2^{13}}:\frac{1}{2}\\\\\\
\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]-\frac{1}{2^{12}} =\frac{1}{2^{12}}\\\\\\
\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot \left( \frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]=\frac{1}{2^{12}}+\frac{1}{2^{12}}
[/tex]
[tex]\displaystyle\\
\frac{1}{2^2}\cdot\left[\frac{1}{2^3}\cdot\left(\frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}\right]=\frac{1}{2^{11}}\\\\\\
\frac{1}{2^3}\cdot\left(\frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}=\frac{1}{2^{11}}:\frac{1}{2^2}\\\\\\
\frac{1}{2^3}\cdot \left(\frac{1}{2^4}-\frac{x}{2^5}\right)-\frac{1}{2^9}=\frac{1}{2^{9}}\\\\\\
\frac{1}{2^3}\cdot\left(\frac{1}{2^4}-\frac{x}{2^5}\right)=\frac{1}{2^{9}}+\frac{1}{2^9}
[/tex]
[tex]\displaystyle\\
\frac{1}{2^3}\cdot\left(\frac{1}{2^4}-\frac{x}{2^5}\right)=\frac{1}{2^8}\\\\\\
\frac{1}{2^4}-\frac{x}{2^5}=\frac{1}{2^8}:\frac{1}{2^3}\\\\\\
\frac{1}{2^4}-\frac{x}{2^5}=\frac{1}{2^5}\\\\\\
\frac{1}{2^4}-\frac{x}{2^5}=\frac{1}{2^5}\\\\\\
\frac{x}{2^5}=\frac{1}{2^4}-\frac{1}{2^5}\\\\\\
\frac{x}{2^5}=\frac{1}{2^5}\\\\
\boxed{\bf x = 1}[/tex]
