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Calculati suma 1^2 – 2^2 + 3^2 – ... ±n^2.
Daca puteti in C, dar nu ma deranjeaza nici C++.


Răspuns :

In C++ :
#include <iostream>
using namespace std;
int main(){
int n,i,s=0;
cin>>n;
i=1;
while(i<=n)
{s=s+i*2;
i=(i+1)*(-1);}
cout<<s;
return 0;
}